(4y^3-3y)/(2y+1)

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Solution for (4y^3-3y)/(2y+1) equation:


D( y )

2*y+1 = 0

2*y+1 = 0

2*y+1 = 0

2*y+1 = 0 // - 1

2*y = -1 // : 2

y = -1/2

y in (-oo:-1/2) U (-1/2:+oo)

(4*y^3-(3*y))/(2*y+1) = 0

(4*y^3-3*y)/(2*y+1) = 0

4*y^3-3*y = 0

y*(4*y^2-3) = 0

4*y^2 = 3 // : 4

y^2 = 3/4

y^2 = 3/4 // ^ 1/2

abs(y) = (3/4)^(1/2)

y = (3/4)^(1/2) or y = -(3/4)^(1/2)

y*(y-(3/4)^(1/2))*(y+(3/4)^(1/2)) = 0

(y*(y-(3/4)^(1/2))*(y+(3/4)^(1/2)))/(2*y+1) = 0

( y+(3/4)^(1/2) )

y+(3/4)^(1/2) = 0 // - (3/4)^(1/2)

y = -(3/4)^(1/2)

( y-(3/4)^(1/2) )

y-(3/4)^(1/2) = 0 // + (3/4)^(1/2)

y = (3/4)^(1/2)

( y )

y = 0

y in { -(3/4)^(1/2), (3/4)^(1/2), 0 }

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